Countolaf
Level 11 poster
Count Omar, the Wild Warrior
Posts: 1,113
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Post by Countolaf on May 13, 2006 19:41:59 GMT 1
Four pairs go together to a club. Their names are Cintia, Teresa, Aguida, Gladys, Newton, Arquimedes, Pitagoras and Gauss. (Cintia, Teresa, Aguida and Gladys are women and Newton, Arquimedes, Pitagoras and Gauss are men) In a certain moment: 1. Newton's wife doesn't dance with her husband. She dances with Cintia's husband. 2. Arquimedes plays guitar and Aguida plays piano. 3. Gladys and Gauss don't dance. 4. Gladys isn't Arquimedes's wife. 5. Who is Gauss's wife?
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Post by Fox Mc Cloud on May 13, 2006 20:21:07 GMT 1
Arquimedes and Aguida are together, means 6 ppl left. I think one of the names in 1, 2.. or 5 is wrong.
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Countolaf
Level 11 poster
Count Omar, the Wild Warrior
Posts: 1,113
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Post by Countolaf on May 13, 2006 23:04:15 GMT 1
Everything is correct, Fox.
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Post by Fox Mc Cloud on May 14, 2006 10:03:06 GMT 1
I would say Gladys.
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Countolaf
Level 11 poster
Count Omar, the Wild Warrior
Posts: 1,113
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Post by Countolaf on May 14, 2006 12:51:49 GMT 1
How did you guess, Fox?
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Post by Fox Mc Cloud on May 14, 2006 16:20:08 GMT 1
Because they both don't dance but can you explain how it actually works?
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Countolaf
Level 11 poster
Count Omar, the Wild Warrior
Posts: 1,113
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Post by Countolaf on May 14, 2006 17:08:46 GMT 1
We will use O for married with, X for not married with, and - for unknown. 1) We make a table: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | - | - | - | - | Teresa | - | - | - | - | Aguida | - | - | - | - | Gladys | - | - | - | - |
2) Using affirmation 4: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | - | - | - | - | Teresa | - | - | - | - | Aguida | - | - | - | - | Gladys | - | X | - | - |
3) Using affirmation 1: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | X | - | - | - | Teresa | - | - | - | - | Aguida | - | - | - | - | Gladys | - | X | - | - |
4) Using affirmations 1 and 3: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | X | - | - | X | Teresa | - | - | - | - | Aguida | - | - | - | - | Gladys | X | X | - | - |
5) Using affirmations 1 and 2: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | X | X | - | X | Teresa | - | - | - | - | Aguida | X | - | - | - | Gladys | X | X | - | - |
6) Then we get: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | X | X | O | X | Teresa | O | - | - | - | Aguida | X | - | - | - | Gladys | X | X | - | - |
7) Now: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | X | X | O | X | Teresa | O | X | X | X | Aguida | X | - | X | - | Gladys | X | X | X | - |
8) Finally: | Newton | Arquimedes | Pitagoras | Gauss | Cintia | X | X | O | X | Teresa | O | X | X | X | Aguida | X | O | X | X | Gladys | X | X | X | O |
From the table, Gladys is Gauss's wife. You can find faster than this, but I wanted to show all the pairs.
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Post by Fox Mc Cloud on May 14, 2006 19:03:49 GMT 1
Nice explanation .
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